[백준 JAVA] 11021번 A+B

나의 답안 :

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.StringTokenizer;

public class Main {
	public static void main(String[] args) throws IOException {
		BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
		BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
		
        int n = Integer.parseInt(bf.readLine());//테스트케이스개수
	
		for(int i=1; i<=n; i++) {
			StringTokenizer st = new StringTokenizer(bf.readLine()," ");
			int a = Integer.parseInt(st.nextToken());
			int b = Integer.parseInt(st.nextToken());
			bw.write("Case #"+i+": "+(a+b)+"\n");		
		}
		bf.close();
		bw.flush();
		bw.close();		
	}	
	}

 

개선할 점:

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import java.io.IOException;
import java.io.BufferedWriter;
import java.io.OutputStreamWriter;
 
public class Main {
	public static void main(String args[]) throws IOException {
 
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
		
		int a = Integer.parseInt(br.readLine());
 
		StringTokenizer st;
		for (int i = 1; i <= a; i++) {
			st = new StringTokenizer(br.readLine()," ");
			bw.write("Case #"+i+": ");
			bw.write(Integer.parseInt(st.nextToken())		//**
				+Integer.parseInt(st.nextToken())+"\n");
		}
		br.close();
		bw.flush();
		bw.close();
	}
 
}

 

          //굳이 변수 a, b를 선언하지 않고 바로 출력했다. 

 

참고: https://st-lab.tistory.com/33